9w^2-33w-26=0

Solution for 9w^2-33w-26=0 equation:

9w^2-33w-26=0

a = 9; b = -33; c = -26;
Δ = b2-4ac
Δ = -332-4·9·(-26)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-45}{2*9}=\frac{-12}{18}
=-2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+45}{2*9}=\frac{78}{18}
=4+1/3
$